2x^2+20x+320=0

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Solution for 2x^2+20x+320=0 equation:


Simplifying
2x2 + 20x + 320 = 0

Reorder the terms:
320 + 20x + 2x2 = 0

Solving
320 + 20x + 2x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '2'.
2(160 + 10x + x2) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(160 + 10x + x2)' equal to zero and attempt to solve: Simplifying 160 + 10x + x2 = 0 Solving 160 + 10x + x2 = 0 Begin completing the square. Move the constant term to the right: Add '-160' to each side of the equation. 160 + 10x + -160 + x2 = 0 + -160 Reorder the terms: 160 + -160 + 10x + x2 = 0 + -160 Combine like terms: 160 + -160 = 0 0 + 10x + x2 = 0 + -160 10x + x2 = 0 + -160 Combine like terms: 0 + -160 = -160 10x + x2 = -160 The x term is 10x. Take half its coefficient (5). Square it (25) and add it to both sides. Add '25' to each side of the equation. 10x + 25 + x2 = -160 + 25 Reorder the terms: 25 + 10x + x2 = -160 + 25 Combine like terms: -160 + 25 = -135 25 + 10x + x2 = -135 Factor a perfect square on the left side: (x + 5)(x + 5) = -135 Can't calculate square root of the right side. The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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